SOAL UJIAN ILMU FALAQ KE 2

SOAL UJIAN KE 2

Di ketahui data-data sebagai berikut  :          

Lintang Mesjid                                    :           -2° 18’ 27.35” LS

Bujur Mesjid                                       :           109° 37° 50.54° BT

Lintang Ka’bah                                   :           21° 25’ 21.04” LU

Bujur Ka’bah                                      :           39° 49’ 34.33” BT

Jawaban :

1.      Bayangan pada tanggal 12 Maret 2014

Deklinasi Matahari jam 01:00 GMT               :           - 3° 26’ 13”

Equation Of Time                                           :           - 0° 9’ 53”

Kwd (120° - 109° 37’ 50.54”) : 15                 :           0° 41’ 28.63”

Langkah Perhitungan :

a = 90° - δ                   :           90° - -3° 26’ 13”          =          93° 26’ 13”

b = 90° - ҩ                   :           90° - - 2° 18’ 27.35”    =          92° 18’ 27.35”

A                                 :           66° 36’ 37.56”

Cotan P = Cos b tan A

Cotan P = Cos 92° 18’ 27.35” tan 66° 36’ 37.56”

Atau

Shift tan (1 : Cos 92° 18’ 27.35” x Tan 66° 36’ 37.56”) = °’”

P = -84° 40’ 53.62”

Cos (C-P) = Cotan a Tan b Cos P

Cos (C-P) = Cotan 93° 26’ 13” Tan 92° 18’ 27.35” Cos - 84° 40’ 53.62”

Atau

1 : Tan 93° 26’ 13” x Tan 92° 18’ 27.35” x Cos - 84° 40’ 53.62” = Shift Cos = °’”

C-P = 82° 3’ 34.03”

T = (( C-P + P ) : 15 ) + 12 – EOT + Kwd

T = (( 82° 3’ 34.03” + - 84° 40’ 53.62” ) : 15 ) + 12 - - 0° 9’ 53” + 0° 41’ 28.63” = °’”

T = 12° 42’ 44.32”      =          12:42:44.32 WITA

2.      Bayangan pada tanggal 24 April 2014

DeklinasiMatahari jam 07:00 GMT                :           12° 51’ 32”

Equation Of Time                                           :           0° 1’ 49”

Kwd (120° - 109° 37’ 50.54”) : 15 =              :           0° 41’ 28.63”

LangkahPerhitungan :

a = 90° - δ                   :           90° -12° 51’ 32”          =          77° 8’ 28”

b = 90° - ҩ                   :           90° - - 2° 18’ 27,35”    =          92° 18’ 27.35”

A                                 :           66° 36’ 37.56”

Cotan P = Cos b tan A

Cotan P = Cos 92° 18’ 27.35” tan 66° 36’ 37.56”

Atau

Shift tan (1 : Cos 92° 18’ 27.35” x Tan 66° 36’ 37.56”) = °’”

P = -84° 40’ 53.62”

Cos (C-P) = Cotan a Tan b Cos P

Cos (C-P) = Cotan 77° 8’ 28” Tan 92° 18’ 27.35” Cos - 84° 40’ 53.62”

Atau

1 : Tan 77° 8’ 28”x Tan 92° 18’ 27.35” x Cos - 84° 40’ 53.62” = - 0.525079152 Shift Cos = °’”

Cos = 121° 40’ 24.8”

C-P = 121° 40’ 24.8”

T = (( C-P + P ) : 15 ) + 12 – EOT + Kwd

T = ((121° 40’ 24.8”+ - 84° 40’ 53.62” ) : 15 ) + 12 - 0° 1’ 49” + 0° 41’ 28.63” = °’”

T = ° ’ 44.81”  =          12:57:44.81 WITA

3.      Bayangan pada tanggal 30 September 2014

Deklinasi Matahari jam 01:00 GMT               :           -2° 42’ 01”

Equation Of Time                                           :           0° 9’ 49”

Kwd (120° - 109° 37’ 50.54”) : 15 =              :           0° 41’ 28.63”

LangkahPerhitungan :

a = 90° - δ                   :           90° --2° 42’ 01”           =          92° 42’ 1”

b = 90° - ҩ                   :           90° - - 2° 18’ 27,35”    =          92° 18’ 27.35”

A                                 :           66° 36’ 37.56”

Cotan P = Cos b tan A

Cotan P = Cos 92° 18’ 27.35” tan 66° 36’ 37.56”

Atau

Shift tan (1 : Cos 92° 18’ 27.35” x Tan 66° 36’ 37.56”) = °’”

P = -84° 40’ 53.62”

Cos (C-P) = Cotan a Tan b Cos P

Cos (C-P) = Cotan 92° 42’ 1” Tan 92° 18’ 27.35” Cos - 84° 40’ 53.62”

Atau

1 : Tan 92° 42’ 1”x Tan 92° 18’ 27.35” x Cos - 84° 40’ 53.62” = 0.108485806 Shift Cos = °’”

C-P = 83° 46’ 19.07”

T = (( C-P + P ) : 15 ) + 12 – EOT + Kwd

T = ((83° 46’ 19.07”+ - 84° 40’ 53.62” ) : 15 ) + 12 -0° 9’ 49” + 0° 41’ 28.63” = °’”

T = 12° 28’ 1.33”        =          12:28:01.33 WITA